Association of Soluble ST2 With Functional Outcome, Perihematomal Edema, and Immune Response After Intraparenchymal Hemorrhage

可溶性 ST2 与脑实质出血后功能结果、血肿周围水肿和免疫反应的关联

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作者:Matthew B Bevers, Caroline Booraem, Karen Li, Anirudh Sreekrishnan, Cristina Sastre, Guido J Falcone, Kevin Navin Sheth, Lauren H Sansing, W Taylor Kimberly

Discussion

Our findings demonstrate that elevated sST2 links the peripheral innate immune response to PHE volume and outcome after IPH. This knowledge is relevant to future studies that seek to identify patients with IPH at highest risk for immune-mediated injury or limit injury through targeted interventions.

Methods

Patients with deep IPH were enrolled within 36 hours of ictus, and blood was collected for sST2 and immune cell measurement. Hematoma volume and PHE were measured on serial CT scans. Good outcome was defined as a modified Rankin Scale score of 0-3 at 90 days. Linear mixed-effects models were used to analyze the relationship between sST2 and PHE over time. Flow cytometry was used to identify shifts in immune cell populations associated with sST2. Immunohistochemistry of human brain tissue was used to identify ST2-expressing cells in the perihematomal region.

Results

The 55 included patients had a median admission Glasgow Coma Scale score of 14 (interquartile range [IQR] 9-15), an intracerebral hemorrhage (ICH) score of 1 (IQR 1-2), and a hematoma volume of 8.6 mL (IQR 3.4-13.8 mL). Receiver operating curve analysis found the sST2 level to be predictive of poor outcome with an area under the curve of 0.763 (95% CI 0.632-0.894) and Youden optimum cut point of 61.8 ng/mL (p < 0.001). sST2 remained an independent predictor after adjustment for ICH score (adjusted odds ratio 2.53, 95% CI 1.03-6.19, p = 0.042). Measurement of PHE found those patients with high sST2 to have greater edema volume over time (β = 1.07, 95% CI 0.51-1.63, p < 0.001). High sST2 was associated with a shift toward an innate peripheral immune response (monocytes and natural killer cells; 68.6% ± 5.1% vs 47.5% ± 4.0%; p = 0.003).

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