Endothelial biomarkers as predictors for haemodialysis need in severe leptospirosis patients (Weil's disease)

内皮生物标志物作为严重钩端螺旋体病(魏尔氏病)患者血液透析需求的预测指标

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作者:Gdayllon Cavalcante Meneses, Pedro Eduardo Andrade de Carvalho Gomes, Gabriela Studart Galdino, Gabriela Freire Bezerra, Ranieri Sales de Souza Santos, Alice Maria Costa Martins, Geraldo Bezerra da Silva Junior, Alexandre Braga Libório, Roberto da Justa Pires Neto, Elizabeth De Francesco Daher

Conclusion

Syndecan-1 and angiopoietin-2 were associated with haemodialysis need in patients with severe leptospirosis and may be useful to improve therapeutic approach and reduce mortality.

Methods

Prospective study with severe leptospirosis patients hospitalised in Fortaleza, Brazil. Blood samples were collected hospital admission to quantify vascular injury biomarkers: syndecan-1, ICAM-1, VCAM-1, angiopoietin-2 and FGF-23. Two groups were evaluated according to haemodialysis requirement during hospital stay.

Objective

To investigate the prediction ability of vascular injury biomarkers for haemodialysis requirement in patients with severe leptospirosis.

Results

Twenty-seven patients were included, with a mean age of 39 ± 18 years. 88.9% were males. 53.8% needed haemodialysis and presented higher levels on hospital admission of syndecan-1 (572 [300-811] vs. 263 [106-421] ng/ml; p = 0.03), angiopoietin-2 (1.52 [0.72-2.72] vs. 0.63 [0.4-1.38] ng/ml; p = 0.01), and FGF-23 (291 [56-2031] vs. 10 [10-806] pg/ml; p = 0.021). Syndecan-1 showed significant correlation with creatinine (r = 0.546; p = 0.05) and total bilirubin levels (r = 0.534; p = 0.013) on hospital admission. Angiopoietin-2 showed significant correlation with creatinine levels (r = 0.513; p = 0.009) on hospital admission and with number of haemodialysis sessions (r = 0.406; p = 0.049). No significant correlation was found with FGF-23. Regarding prognostic performance, combined syndecan-1 and angiopoietin-2 levels had a better ability to predict haemodialysis need in patients with severe leptospirosis (AUC-ROC = 0.744 [95% CI: 0.545-0.943] p = 0.035).

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