Abstract
The competition for glucose between Escherichia coli ML30, a typical copiotrophic enterobacterium and Chelatobacter heintzii ATCC29600, an environmentally successful strain, was studied in a carbon-limited culture at low dilution rates. First, as a base for modelling, the kinetic parameters μ(max) and K(s) were determined for growth with glucose. For both strains, μ(max) was determined in batch culture after different precultivation conditions. In the case of C. heintzii, μ(max) was virtually independent of precultivation conditions. When inoculated into a glucose-excess batch culture medium from a glucose-limited chemostat run at a dilution rate of 0.075 h(-1) C. heintzii grew immediately with a μ(max) of 0.17 ± 0.03 h(-1). After five transfers in batch culture, μ(max) had increased only slightly to 0.18 ± 0.03 h(-1). A different pattern was observed in the case of E. coli. Inoculated from a glucose-limited chemostat at D = 0.075 h(-1) into glucose-excess batch medium E. coli grew only after an acceleration phase of ~3.5 h with a μ(max) of 0.52 h(-1). After 120 generations and several transfers into fresh medium, μ(max) had increased to 0.80 ± 0.03 h(-1). For long-term adapted chemostat-cultivated cells, a K(s) for glucose of 15 μg l(-1) for C. heintzii, and of 35 μg l(-1) for E. coli, respectively, was determined in (14)C-labelled glucose uptake experiments. In competition experiments, the population dynamics of the mixed culture was determined using specific surface antibodies against C. heintzii and a specific 16S rRNA probe for E. coli. C. heintzii outcompeted E. coli in glucose-limited continuous culture at the low dilution rates of 0.05 and 0.075 h(-1). Using the determined pure culture parameter values for K(s) and μ(max), it was only possible to simulate the population dynamics during competition with an extended form of the Monod model, which includes a finite substrate concentration at zero growth rate (s(min)). The values estimated for s(min) were dependent on growth rate; at D = 0.05 h(-1), it was 12.6 and 0 μg l(-1) for E. coli and C. heintzii, respectively. To fit the data at D=0.075 h(-1), s(min) for E. coli had to be raised to 34.9 μg l(-1) whereas s(min) for C. heintzii remained zero. The results of the mathematical simulation suggest that it is not so much the higher K(s) value, which is responsible for the unsuccessful competition of E. coli at low residual glucose concentration, but rather the existence of a significant s(min).